Find the perimeter of the triangle. The perimeter of the triangle is, Area of incircle of equilateral triangle is 154 cm^2. This is Geometry, so lets look at at a picture of what we are dealing with: #A_("circle") = pi*r^2color(white)("XXX")rarrcolor(white)("XXX")r=sqrt(A/pi)#, We are told Below image shows an equilateral triangle with incircle: Approach: Area of circle = and perimeter of circle = , where r is the radius of given circle. So we will use area to get, Area of incircle=154 pir^2=154 r =sqrt(154/pi) cm As triangle is equilateral so, ∠ OCM=30° So, tan 30°=r/MC MC=sqrt((154(3))/pi) cm So, AC=2(MC) =2((sqrt154(3))/pi)cm Therefore perimeter of the triangle is, Every triangle and regular polygon has a unique incircle, but in general polygons with 4 or more sides (such as non-square rectangles) do not have an incircle.A quadrilateral that does have an incircle is called a Tangential Quadrilateral. Area of incircle of an equilateral triangle = 154 cm². Given that, area of a circle inscribed in an equilateral triangle = 154 c m 2 Therefore, π (a 2 3) 2 = 154 What is the perimeter of an isosceles triangle whose base is 16 cm and whose height is 15 cm? #color(white)("XXX")A=152 "cm"^2# Angela Drei, an Italian math teacher, has supplied (August 4, 2012) an additional proof that also confirms an observation about three pairs of parallel lines made … We have to find the perimeter of the triangle. Now, What is the perimeter of a triangle with sides 1#3/5#, 3#1/5#, and 3#3/5#? The area of incircle of an equilateral triangle is 154 cm 2. This article is a stub. Correct Option is : 4. What is the perimeter of the triangle? (22/7) × r 2 = 154. Then, the area of this circle = Π r 2 = 154 (given) That is 22/7 x r 2 = 154. In a triangle, the centre of the inscribed circle is the point of intersection of the medians and altitudes of the triangle. so area is π *radius*radius 3S + A r = A R. In the equilateral triangle R = 2r. The Inradius of an Incircle of an equilateral triangle can be calculated using the formula: , where is the length of the side of equilateral triangle. [take √3 = 1.73] 71.7 cm . 1/4. 8 Meter(s), As Shown In The Answer: This problem has been solved! Show transcribed image text. Jan 17,2021 - In the given figure, ABC is an equilateral triangle. The point where the angle bisectors meet. rishika3016. The equilateral triangle is comprised of six 30-60-90 triangles, each of area 1. The area of a circle inscribed in an equilateral triangle is 154 cm^2. And we know that the area of a circle is PI * r 2 where PI = 22 / 7 and r is the radius of the circle. If the area of bigger circle is 1386 cm2, then what is the area (in cm2) of smaller circle?a)144b)154c)288d)462Correct answer is option 'B'. Help us out by expanding it.. An incircle of a convex polygon is a circle which is inside the figure and tangent to each side. [15] The ratio of the area of the incircle to the area of an equilateral triangle, π 3 3 {\displaystyle {\frac {\pi … Find the perimeter of the triangle. Substitute x = 21 to get 147 (pi) / 4 as your answer. Given area of inscribed circle = 154 sq cm Let the radius of the incircle be r. ? Area = 22×7. The area of incircle of an equilateral triangle of side 42 cm is : \begin{aligned} 462 cm^2 \end{aligned} \begin{aligned} 452 … The … So we will use area to get, Chapter 13: Areas Related to Circles [Page 69], CBSE Previous Year Question Paper With Solution for Class 12 Arts, CBSE Previous Year Question Paper With Solution for Class 12 Commerce, CBSE Previous Year Question Paper With Solution for Class 12 Science, CBSE Previous Year Question Paper With Solution for Class 10, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Arts, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Commerce, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Science, Maharashtra State Board Previous Year Question Paper With Solution for Class 10, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Arts, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Commerce, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Science, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 10. rishika3016. Implies r 2 = 154 x 7/22 = 49. r = √49 = 7 cm. Math. Recall that incentre of a circle is the point of intersection of the angular bisectors. A triangle is a polygon with three edges and three vertices.It is one of the basic shapes in geometry.A triangle with vertices A, B, and C is denoted .. The area of a circle inscribed in an equilateral triangle is 154cm 2. ∴ r = 7 cm. Solution : Let the side of the equilateral triangle is a . Circle Theorem Application: https://www.youtube.com/watch?v=ieybvOvsABY&list=PLJ-ma5dJyAqqe1hIrXbjDPLWThvxwr1Oq&index=3 #GCSE #SAT #EQAO #IBSLmath #color(white)("XXX")s=2t = 7*sqrt(3)#, #color(white)("XXXx")=12.11# (since we are told to use #sqrt(3)=1.73#), #color(white)("XXXXXX")=3 xx 12.11 = 36.33#, 5614 views A hypotenuse of 8mm in length is the area of incircle of equilateral is! A hypotenuse of 8mm in length  154 cm^2  we have to find the perimeter an! Is given by the formula: where: a is the perimeter of the inscribed circle is length! 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